Java Integer Cache – Why Integer.valueOf(127) == Integer.valueOf(127) Is True
In an interview, one of my friends was asked that if we have two Integer objects, Integer a = 127; Integer b = 127;
Why a == b
evaluate to true
when both are holding two separate objects? In this article, I will try to answer this question and also try to explain the answer.
Short Answer
The short answer to this question is, direct assignment of an int
literal to an Integer
reference is an example of auto-boxing concept where the literal value to object conversion code is handled by the compiler, so during compilation phase compiler converts Integer a = 127;
to Integer a = Integer.valueOf(127);
.
TheInteger
class maintains an internal IntegerCache for integers which by default ranges from -128 to 127
andInteger.valueOf()
method returns objects of mentioned range from that cache. So a == b
returns true because a
and b
both are pointing to the same object.
Long Answer
In order to understand the short answer let’s first understand the Java types, all types in Java lies under two categories
- Primitive Types: There are 8 primitive types (byte, short, int, long, float, double, char and boolean) in Java which holds their values directly in the form of binary bits.
For exampleint a = 5; int b = 5;
, herea
andb
directly holds the binary value of 5 and if we try to comparea
andb
usinga == b
we are actually comparing5 == 5
which returns true. - Reference Types: All types other than primitive types lies under the category of reference types e.g. Classes, Interfaces, Enums, Arrays etc. and reference types holds the address of the object instead of the object iteslf.
For example,Integer a = new Integer(5); Integer b = new Integer(5)
, here a and b do not hold the binary value of5
insteada
andb
holds memory addresses of two separate objects where both objects contain a value5
. So if we try to comparea
andb
usinga == b,
we are actually comparing those two separate memory addresses hence we getfalse
, to perform actual equality ona
andb
we need to performa.euqals(b)
. Reference types are further divided into 4 categories Strong, Soft, Weak and Phantom References.
And we know that Java provides wrapper classes for all primitive types and support auto-boxing and auto-unboxing.
// Example of auto-boxing, here c is a reference type Integer c = 128; // Compiler converts this line to Integer c = Integer.valueOf(128); // Example of auto-unboxing, here e is a primitive type int e = c; // Compiler converts this line to int e = c.intValue();
Now if we create two integer objectsa
andb,
and try to compare them using the equality operator==
, we will getfalse
because both references are holding different-different objects
Integer a = 128; // Compiler converts this line to Integer a = Integer.valueOf(128); Integer b = 128; // Compiler converts this line to Integer b = Integer.valueOf(128); System.out.println(a == b); // Output -- false
But if we assign the value 127
to both a
and b
and try to compare them using the equality operator ==
, we will get true
why?
Integer a = 127; // Compiler converts this line to Integer a = Integer.valueOf(127); Integer b = 127; // Compiler converts this line to Integer b = Integer.valueOf(127); System.out.println(a == b); // Output -- true
As we can see in the code that we are assigning different objects to a
and b
but a == b
can return true only if both a
and b
are pointing to the same object.
So how the comparison returning true? whats actually happening here? are a
and b
pointing to the same object?
Well till now we know that the code Integer a = 127;
is an example of auto-boxing and compiler automatically converts this line to Integer a = Integer.valueOf(127);
.
So it is the Integer.valueOf()
method which is returning these integer objects which means this method must be doing something under the hood.
And if we take a look at the source code of Integer.valueOf()
method, we can clearly see that if the passed int literal i
is greater than IntegerCache.low
and less thanIntegerCache.high
then the method returns Integer objects fromIntegerCache
. Default values for IntegerCache.low
and IntegerCache.high
are -128
and 127
respectively.
In other words, instead of creating and retruning new integer objects, Integer.valueOf()
method returns Integer objects from an internal IntegerCache
if the passed int literal is greater than
-128
and less than 127
.
/** * Returns an {@code Integer} instance representing the specified * {@code int} value. If a new {@code Integer} instance is not * required, this method should generally be used in preference to * the constructor {@link #Integer(int)}, as this method is likely * to yield significantly better space and time performance by * caching frequently requested values. * * This method will always cache values in the range -128 to 127, * inclusive, and may cache other values outside of this range. * * @param i an {@code int} value. * @return an {@code Integer} instance representing {@code i}. * @since 1.5 */ public static Integer valueOf(int i) { if (i >= IntegerCache.low && i <= IntegerCache.high) return IntegerCache.cache[i + (-IntegerCache.low)]; return new Integer(i); }
Java caches integer objects which fall into -128 to 127 range because this range of integers gets used a lot in day to day programming which indirectly saves some memory.
As you can see in the following image Integer
class maintains an inner static IntegerCache
class which acts as the cache and holds integer objects from -128 to 127 and that’s why when we try to get integer object for 127
we always get the same object.
The cache is initialized on first usage when the class get loaded into memory because of the static block
. The max range of the cache can be controlled by the -XX:AutoBoxCacheMax
JVM option.
This caching behavior is not applicable for Integer
objects only, similar to Integer.IntegerCache
we also haveByteCache
,ShortCache
,LongCache
,CharacterCache
forByte
, Short
,
Long
,Character
respectively.
Byte, Short and Long have a fixed range for caching between –127 to 127 (inclusive) but for Character, the range is from 0 to 127 (inclusive). The range can be modified via argument only for Integer but not for others.
You can find the complete source code for this article on this Github Repository and please feel free to provide your valuable feedback.
Published on Java Code Geeks with permission by Naresh Joshi, partner at our JCG program. See the original article here: Java Integer Cache – Why Integer.valueOf(127) == Integer.valueOf(127) Is True Opinions expressed by Java Code Geeks contributors are their own. |