Core Java

How to convert String to int in Java

Photo of Gaurav Bhardwaj Gaurav BhardwajMarch 26th, 2020Last Updated: March 23rd, 2020
1 703 2 minutes read

In this tutorial, we will see the various ways in which we can convert String to int(or Integer) in Java.

You can use any of the following ways :

– Using Integer.parseInt(string)

– Using Integer.valueof(string)

– Using Apache commons NumberUtils.toInt(string)

– Using Apache commons  NumberUtils.createInteger(string)

– Using Guava library’s Ints.tryParse(string) method

– Using Integer.decode(string)

– Using new Integer(string)

Using Integer.parseInt(string)

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String empId1 = "1001";
int intEmpId1 = Integer.parseInt(empId1);
System.out.println(intEmpId1);
 
Output :
1001

Integer.parseInt() will throw NumberFormatException in following cases:

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/ Alphabets in the input.
 Integer.parseInt("100AB");
 
//Input number is greater than the Integer range.
 Integer.parseInt("2147483648");
   
//Number with decimal
 Integer.parseInt("1.1");
 
 //empty String
 Integer.parseInt("");
   
 //Blank space
 Integer.parseInt(" ");

Using Integer.valueof(string)

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String empId2 = "2001";
 
Integer integerEmpId2 = Integer.valueOf(empId2);
System.out.println(integerEmpId2);
 
Output :
2001

Using Apache commons NumberUtils.toInt(string)

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String empId3 = "3001";
int intEmpId3 = NumberUtils.toInt(empId3);
System.out.println(intEmpId3);
 
Output :
3001
 
   
int intEmpId4 = NumberUtils.toInt(null);
System.out.println(intEmpId4);
 
Output :
0
 
   
int intEmpId5 = NumberUtils.toInt("1001ABC");
System.out.println(intEmpId5);
 
Output :
0
 
   
int intEmpId6 = NumberUtils.toInt("1001ABC", 10);
System.out.println(intEmpId6);
 
Output :
10

Using Apache commons  NumberUtils.createInteger(string)

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String empId4 = "4001";
Integer integerEmpId7 = NumberUtils.createInteger(empId4);
System.out.println(integerEmpId7);
 
Output :
4001

Using Guava library’s Ints.tryParse(string) method

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String empId5 = "5001";
Integer integerEmpId8 = Ints.tryParse(empId5);
 
System.out.println(integerEmpId8);
 
Output :
5001

Using Integer.decode(string)

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String empId6 = "6001";
Integer integerEmpId9 = Integer.decode(empId6);
System.out.println(integerEmpId9);
 
Output :
6001

Using new Integer(string)

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String empId7 = "7001";
Integer integerEmpId10 = new Integer(empId7);
System.out.println(integerEmpId10);
 
Output :
7001

However, remember that this Integer constructor is deprecated since Java9.

Complete Program 

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package com.blogspot.javasolutionsguide.stringtointexample;
 
import org.apache.commons.lang3.math.NumberUtils;
import com.google.common.primitives.Ints;
 
public class StringToInt {
  
 public static void main(String[] args) {
  String empId1 = "1001";
                int intEmpId1 = Integer.parseInt(empId1);
  System.out.println(intEmpId1);
   
  String empId2 = "2001";
  Integer integerEmpId2 = Integer.valueOf(empId2);
  System.out.println(integerEmpId2);
   
  String empId3 = "3001";
  int intEmpId3 = NumberUtils.toInt(empId3);
  System.out.println(intEmpId3);
   
  int intEmpId4 = NumberUtils.toInt(null);
  System.out.println(intEmpId4); 
   
  int intEmpId5 = NumberUtils.toInt("1001ABC");
  System.out.println(intEmpId5);
 
  int intEmpId6 = NumberUtils.toInt("1001ABC", 10);
  System.out.println(intEmpId6);
   
  String empId4 = "4001";
  Integer integerEmpId7 = NumberUtils.createInteger(empId4);
  System.out.println(integerEmpId7);
   
  String empId5 = "5001";
  Integer integerEmpId8 = Ints.tryParse(empId5);
  System.out.println(integerEmpId8);
   
  String empId6 = "6001";
  Integer integerEmpId9 = Integer.decode(empId6);
  System.out.println(integerEmpId9);
   
  String empId7 = "7001";
  Integer integerEmpId10 = new Integer(empId7);
  System.out.println(integerEmpId10);
   
  // Alphabets in the input.
   Integer.parseInt("100AB");
 
  //Input number is greater than the Integer range.
   Integer.parseInt("2147483648");
 
  //Number with decimal
   Integer.parseInt("1.1");
 
   //empty String
   Integer.parseInt("");
 
   //Blank space
   Integer.parseInt(" ");
 }
}

Dependencies used :

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<dependency>
    <groupId>org.apache.commons</groupId>
    <artifactId>commons-lang3</artifactId>
    <version>3.9</version>
</dependency>
 
<dependency>
    <groupId>com.google.guava</groupId>
    <artifactId>guava</artifactId>
    <version>16.0.1</version>
 
</dependency>

Summary

So, in this tutorial, we saw

– How we can convert String to int(or Integer) in Java.

– In most of the scenarios we can use Integer.parseInt() and Integer.valueOf(),if we want int or Integer

respectively from String and want to avoid dependency on third party libraries.
– NumberUtils. toInt() can be used in the scenarios ,where we don’t want our program to fail due NumberFormatException.

Published on Java Code Geeks with permission by Gaurav Bhardwaj, partner at our JCG program. See the original article here: How to convert String to int in Java

Opinions expressed by Java Code Geeks contributors are their own.

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Photo of Gaurav Bhardwaj Gaurav BhardwajMarch 26th, 2020Last Updated: March 23rd, 2020
1 703 2 minutes read
Photo of Gaurav Bhardwaj

Gaurav Bhardwaj

Gaurav has done Masters in Computer Applications(MCA) and is working in Software development field for more than 10 years in Java/J2EE technologies. He is currently working with one of top MNC. He has worked on various frameworks like Struts, Spring, Spring Boot, Angular JS, JSF, Velocity, iBatis, MyBatis, Hibernate, JUnit, Mockito, Dozzer. He likes to explore new technologies and share his thoughts by writing a technical blog. He is the founder of JavaSolutionsGuide.blogspot.com.
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Google Chorme
Google Chorme
5 years ago

Hi…
I’m Elena gillbert.The Integer.parseInt() java method is used primarily in parsing a String method argument into an Integer object. The Integer object is a wrapper class for the int primitive data type of java API.Eventhough the conversion of String to Integer object is a basic stuff, I am suggesting that we should have a mastery on it.

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